3a² + 11a – 42this is factoring in algebra 2 (high school) ​

To factor, [[[1) First multiply coefficient of a² and constant no,That is,3×(-42)=-126Since the resultant no is negative, you should find two such factors of 126 which will give us the coefficient of a (=11) on subracting those factors. 2) Find the factor 126=2×3×3×7 =18×718 and 17 are factors of 126Also,18-7 =11.So they are required factors for factoring,]]]Once you have understood above steps you can solve on your own. All you need to do is split 11 into factors ,take common terms and you will get answer.Answer: 3a²+11a-42=3a²+(18-7)a -42=3a²+18a-7a-42=3a(a+6) -7(a+6)=(a+6)(3a-7)