A circle has a radius of 7/4 units and is centered at (−2.5,−4.4)
Accepted Solution
A:
Answer:[tex](x+2.5)^2+(y+4.4)^2=\dfrac{49}{16}[/tex].Step-by-step explanation:Consider the complete question is " A circle has a radius of 7/4 units and is centered at (−2.5,−4.4). Write the equation of this circle."
The standard form of a circle is
[tex](x-h)^2+(y-k)^2=r^2[/tex]
where, (h,k) is center and r is radius of the circle.
Substitute h=-2.5, k=-4.4 and r=7/4 in the above formula.
[tex](x-(-2.5))^2+(y-(-4.4))^2=(\dfrac{7}{4})^2[/tex]
[tex](x+2.5)^2+(y+4.4)^2=\dfrac{49}{16}[/tex]
Hence the equation of circle is [tex](x+2.5)^2+(y+4.4)^2=\dfrac{49}{16}[/tex].