A ball is thrown vertically upward. After t seconds, its height h (in feet) is given by the function h(t) = 60t - 16t^2 . What is the maximum height that the ball will reach?Do not round your answer.
Accepted Solution
A:
Answer:56.25 feet.Step-by-step explanation:h(t) = 60t - 16t^2Differentiating to find the velocity:v(t) = 60 -32tThis equals zero when the ball reaches its maximum height, so60-32t = 0t = 60/32 = 1.875 secondsSo the maximum height is h(1.875)= 60* 1.875 - 16(1.875)^2= 56.25 feet.