MATH SOLVE

3 months ago

Q:
# How to solve 3,4 and 6

Accepted Solution

A:

Answer:[tex]\large\boxed{3.\ V\approx130.88\ m^3}\\\boxed{4.\ V\approx35.21}\\\boxed{6.\ V\approx1.06\ in^3}[/tex]Step-by-step explanation:3.The formula of a volume of a sphere:[tex]V=\dfrac{4}{3}\pi R^3[/tex]R - radiusWe have R = 3.15 m. Substitute:[tex]V=\dfrac{4}{3}\pi(3.15)^3\approx\dfrac{4}{3}\pi(31.26)\approx\dfrac{4}{3}(3.14)(31.26)\approx130.88\ m^3[/tex]4.The formula of a volume of a cone:[tex]V=\dfrac{1}{3}\pi r^2H[/tex]r - radiusH - heightWe have 2r = 11.6 β r = 5.8 and H = x. Substitute:[tex]V=\dfrac{1}{3}\pi(5.8)^2(x)=\dfrac{1}{3}\pi(33.64)x\approx\dfrac{1}{3}(3.14)(33.64)x\approx35.21[/tex]6.The formula of a volume of a cube:[tex]V=s^3[/tex]s - edgeWe have s = 1.02 in. Substitute:[tex]V=(1.02)^3\approx1.06\ in^3[/tex]