MATH SOLVE

3 months ago

Q:
# The perimeter of a playing field for a certain sport is 320 ft. The field is a? rectangle, and the length is 48 ft longer than the width. Find the dimensions.

Accepted Solution

A:

Answer:length: 104 ftwidth: 56 ftStep-by-step explanation:Let L and W represent the length and width of the field. Then the perimeter is given by ... P = 2(L +W)Filling in the given information, we have ... 320 = 2(L +W) L = W +48 . . . . . . the length is 48 ft longer than the widthUsing the second equation in the first, we get 320 = 2((W +48) +W) 320 = 4W +96 . . . . . . simplify 224 = 4W . . . . . . . . . . subtract 96 56 = W . . . . . . . . . . . . .divide by 4 L = 56 +48 = 104 . . . . find L using the above relationThe width of the field is 56 ft; the length is 104 ft.