MATH SOLVE

5 months ago

Q:
# Write an equation in slope-intercept form of the line through point (6, –1) with slope m=4. Question 6 options: y + 1 = 4(x – 6) y = 4x – 1 y = 4x – 25 y + 6 = 4(x – 1)

Accepted Solution

A:

The slope-intercept form of the equation of a line is

y = mx + b

where m = slope, and b = y-intercept.

We are given the slope, m = 4, so we can already substitute 4 for m in the equation above giving us

y = 4x + b

Now we need to find b.

Since we are given a point on the line, (6, -1), we substitute x and y with the x- and y-coordinates of the point, respectively, and solve for b.

From our point, we have x = 6, and y = -1.

y = 4x + b

-1 = 4(6) + b

-1 = 24 + b

-25 = b

b = -25

Now that we know that b = -25, we substitute b with -25 in y = 4x + b to get our answer:

y = 4x - 25

y = mx + b

where m = slope, and b = y-intercept.

We are given the slope, m = 4, so we can already substitute 4 for m in the equation above giving us

y = 4x + b

Now we need to find b.

Since we are given a point on the line, (6, -1), we substitute x and y with the x- and y-coordinates of the point, respectively, and solve for b.

From our point, we have x = 6, and y = -1.

y = 4x + b

-1 = 4(6) + b

-1 = 24 + b

-25 = b

b = -25

Now that we know that b = -25, we substitute b with -25 in y = 4x + b to get our answer:

y = 4x - 25